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Answer OPTION: D) ReferenceError
Explanation:
The code defines a global variable x with an initial value of 10.
Inside the foo function, a local constant x is defined with a value of 20.
When console.log(x) is executed, it tries to access the value of the local x variable, but due to hoisting, the local variable is in the temporal dead zone and not accessible at that point.
Hence, a ReferenceError is thrown, indicating that the variable x is not yet defined.
Therefore, the output will be a ReferenceError.
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