LeetCode 53: Maximum Subarray | CSharp Solution | Kadane's Algorithm

Published: 21 July 2025
on channel: Code Scribbler
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🔍 Solve the classic #maximumsubarray problem using Kadane's Algorithm in C#. This video walks through finding the contiguous subarray with the largest sum in a given integer array. #leetcode #dynamicprogramming #kadanealgorithm

⏱️ **Time Complexity**: O(n)
🗃️ **Space Complexity**: O(1)

Timestamps
00:00 - Understanding problem statement
00:43 - Brute force approach
02:43 - Big O Notation explained
03:20 - Understanding Kadane's algorithm
05:43 - Kadane's Algorithm - dry run
08:02 - Big O Notation calculated
09:13 - Solution analysis - runtime + memory
09:20 - Conclusion

Key Concepts
📊 Kadane's Algorithm
🧩 Dynamic Programming
🔄 Array Traversal
🔢 Subarray Handling

Learning Points
💡 Understanding how to identify maximum sum subarrays
💡 Implementing Kadane's Algorithm efficiently
💡 Handling negative numbers in arrays
💡 Converting O(n²) solutions to O(n) solutions

Related Problems
📝 LeetCode 121: Best Time to Buy and Sell Stock
📝 LeetCode 152: Maximum Product Subarray
📝 LeetCode 918: Maximum Sum Circular Subarray
📝 LeetCode 1186: Maximum Subarray Sum with One Deletion

Target Audience
This video is perfect for software engineers preparing for technical interviews, computer science students learning algorithms, and anyone interested in efficient array processing techniques.

Prerequisites
Basic understanding of C# syntax
Familiarity with arrays and loops
Understanding of time and space complexity analysis

Links
🔗 Problem: https://leetcode.com/problems/maximum...
🔗 Solution Code: https://leetcode.com/problems/maximum...

Additional Tips
Pay special attention to how we handle negative numbers in the array
Notice how we track both the current sum and maximum sum seen so far
The algorithm makes a single pass through the array - efficiency is key!

Call to Action
🔔 Subscribe for weekly coding interview prep videos! If you have questions about Kadane's Algorithm or need clarification on any part of the solution, drop them in the comments below. I personally respond to all comments within 24 hours!


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