DSA-Day 4
Question: Given the head of a singly linked list, reverse the list, and return the reversed list.
Approach: Reverse the linked list using three pointers, one to point to the current node, the next node and the previous node. We reverse the reference of each pointer and move the current pointer forward until we reach the end of the Linked List.
Space complexity: O(1)
Time complexity: O(n)
Code: https://github.com/LeandrAnders0n/DSA-/blo...
Music: https://pixabay.com/music/search/abstract%...
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