Python Daily Question - 128
Python Daily Question - 128
Explanation:
1. Initialization:
a = 1
The variable a is initialized to 1.
2. Outer Loop:
for i in range(2, 6):
The outer loop runs with i taking values from 2 to 5 (inclusive).
3. Inner Loop:
for j in range(2, 5):
The inner loop runs with j taking values from 2 to 4 (inclusive).
4. Update a:
a = a + (i + j)
For each combination of i and j, the value of a is updated by adding (i + j).
Iteration Details:
Let's go through each iteration step-by-step:
Initial value of a: a = 1
First outer loop (i = 2):
j = 2: a = a + (2 + 2) = 1 + 4 = 5
j = 3: a = a + (2 + 3) = 5 + 5 = 10
j = 4: a = a + (2 + 4) = 10 + 6 = 16
Second outer loop (i = 3):
j = 2: a = a + (3 + 2) = 16 + 5 = 21
j = 3: a = a + (3 + 3) = 21 + 6 = 27
j = 4: a = a + (3 + 4) = 27 + 7 = 34
Third outer loop (i = 4):
j = 2: a = a + (4 + 2) = 34 + 6 = 40
j = 3: a = a + (4 + 3) = 40 + 7 = 47
j = 4: a = a + (4 + 4) = 47 + 8 = 55
Fourth outer loop (i = 5):
j = 2: a = a + (5 + 2) = 55 + 7 = 62
j = 3: a = a + (5 + 3) = 62 + 8 = 70
j = 4: a = a + (5 + 4) = 70 + 9 = 79
Final Value:
After all iterations, the final value of a is 79.
So, The Final Answer = 79
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