🐍Python Program #14: Check if a Year is a Leap Year | Python Programming
🐍Python Program #14: Check if a Year is a Leap Year | Python Programming
📅 Is it a leap year or not? Learn how to check it using Python in a few easy steps! This program is beginner-friendly and explains the logic clearly with real-world examples.
🎯 You'll Learn:
Leap year rules
if-else statements in Python
Clean input/output structure
Logic:
1. Ask the user to enter a year → e.g., 2024
2. A year is a leap year if:
✅ It's divisible by 4
❌ Except years divisible by 100 (they’re not leap years)
✅ But if divisible by 400, it's a leap year again!
3. Example:
2000 is a leap year (divisible by 400)
1900 is not a leap year (divisible by 100 but not 400)
2024 is a leap year (divisible by 4 and not 100)
4. Use if-elif-else statements to check the condition.
5. Print result accordingly.
Code:
Check if a year is a leap year
year = 2024
if (year % 4 == 0):
if (year % 100 == 0):
if (year % 400 == 0):
print(f"{year} is a leap year.")
else:
print(f"{year} is not a leap year.")
else:
print(f"{year} is a leap year.")
else:
print(f"{year} is not a leap year.")
👉 Perfect for Python beginners and school/college projects!
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