Day 3 - Code Java Smart | Odd or Even

Published: 19 February 2025
on channel: Sourabh Jain

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Welcome to Code Java Smart, where we explore efficient and optimized approaches to Java programming. In today’s video, we explore a smarter and more optimized approach to determine whether a number is odd or even in Java.

Why This Approach? Most people check odd/even using % (modulo) operator, but did you know there’s a faster way .Instead of n % 2 == 0, we use bitwise AND:
(n & 1) == 0 → True for EVEN
(n & 1) == 1 → False for ODD

In This Video, You’ll Learn:
✅ Why bitwise operations are faster than modulo
✅ How (n & 1) works internally
✅ Java implementation with step-by-step explanation
✅ Performance benefits of using bitwise over modulo

Study resources :
https://github.com/Jain131102/Code-Ja...
https://www.geeksforgeeks.org/check-w...
Connect with me:
https://bento.me/sourabh-jain

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#CodeJavaSmart #javaprogramming #bitwiseoperators #efficientcoding #optimization #javatricks #evenodd #smartprogramming #codeitup #code #smart #modulus #division #binary #numbers

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