Two Pointers 2 - Medium - Remove Duplicates from Sorted Array - Java
Coding Interviews - Remove Duplicates from Sorted Array (LeetCode)
This interview question is commonly asked by companies like Facebook Adobe, Amazon.
As the input array is sorted, therefore, we will shift the elements left whenever we encounter duplicates. In other words, we will keep one pointer for iterating the array and one pointer for placing the next non-duplicate number. So our algorithm will be to iterate the array and whenever we see a non-duplicate number we move it next to the last non-duplicate number we’ve seen
Time Complexity -
The time complexity of the above algorithm will be O(N), where ‘N’ is the total number of elements in the given array.
Space Complexity -
The algorithm runs in constant space O(1).
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