LeetCode 34 Explained | Find First and Last Position Using Binary Search | Python
In this video, we solve LeetCode 34: Find First and Last Position of Element in Sorted Array using Python.
The array is sorted, but it may contain duplicate values. A normal binary search can find the target, but it may not find its exact starting and ending positions.
To solve this problem in O(log n) time, we perform two modified binary searches:
One binary search finds the first occurrence.
Another binary search finds the last occurrence.
Using the example:
nums = [5, 7, 7, 8, 8, 10]
target = 8
The target starts at index 3 and ends at index 4, so the answer is:
[3, 4]
In this video, you will learn:
How to modify binary search to find boundaries
How to find the first occurrence of a target
How to find the last occurrence of a target
Why returning immediately after finding the target is incorrect
How to maintain O(log n) time complexity
How to handle empty arrays and missing targets
Complexity
Time Complexity: O(log n)
Space Complexity: O(1)
This is an important binary-search pattern frequently used in coding interviews and array problems.
#LeetCode #BinarySearch #Python #DSA #CodingInterview #Programming #CoinsLive
On this page of the site you can watch the video online LeetCode 34 Explained | Find First and Last Position Using Binary Search | Python with a duration of hours minute second in good quality, which was uploaded by the user coinslive 23 July 2026, share the link with friends and acquaintances, this video has already been watched 3 times on youtube and it was liked by 0 viewers. Enjoy your viewing!
