Selenium Real time Interview Question||How to find unique elementwith insertionorder Java Interview?

Publicado el: 10 julio 2022
en el canal de: Selenium Automation Testing

308

"Solution 1 : with Time Complexity = O(nxn)

Our first solution is very simple. All we are doing here is to loop over an array and comparing each element to every other element. Since we are comparing every element to every other element
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Solution 2 : with Time Complexity = O(n)
Set doesn't allow duplicates in Java. if you have added an element into Set and trying to insert duplicate element again, it will not be allowed.
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Solution 3 : with Time Complexity =0(n)
Linked HashSet doesn't allow duplicates in java and insertion order preserved
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