Reverse Integer - LeetCode 7 | Python Optimal Solution | Handling Integer Overflow
Hi everyone! I’m Nupur, and today we are tackling LeetCode 7: Reverse Integer.
At first glance, this problem seems simple—just reverse the digits, right? But the real challenge lies in the constraints. We are dealing with a 32-bit signed integer range, and if the reversed number exceeds that range, we must return 0. In this video, I'll show you how to solve this mathematically using the modulo and division operators without converting the number to a string.
What we cover:
Problem Analysis: Understanding the 32-bit integer limits (-2^{31} to 2^{31} - 1).
The Logic: Using % 10 to get the last digit and // 10 to shrink the number.
The Overflow Trick: How to check if your number is about to "explode" before it actually does.
Step-by-Step Code: Implementation in Python.
Complexity: Time O(log{10}(x)) and Space O(1).
This is a great problem to practice your basic math logic for campus placements and GATE 2026 prep. Don't forget to Like and Subscribe to follow my daily DSA journey!
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En esta página del sitio puede ver el video en línea Reverse Integer - LeetCode 7 | Python Optimal Solution | Handling Integer Overflow de Duración hora minuto segunda en buena calidad , que subió el usuario Beyond limits 07 febrero 2026, comparta el enlace con amigos y conocidos, en youtube este video ya ha sido visto 18 veces y le gustó 4 a los espectadores. Disfruta viendo!
