In this video, I solve LeetCode 350: Intersection of Two Arrays II using a Map-based frequency count approach in JavaScript.
Unlike LeetCode 349 (unique intersection), this version requires you to include duplicates as many times as they appear in both arrays.
✅ Step-by-step breakdown:
Count each number in nums1 using a Map
Iterate over nums2 and check if the number exists with positive count
Add to result array and decrement the count
Time Complexity: O(n + m)
Space Complexity: O(n)
This solution is fast, easy to read, and perfect for interviews where you’re asked to manage element frequency.
Chapters:
0:00 - Problem Explanation
1:18 - Strategy Overview
3:50 - JavaScript Code Walkthrough
5:23 - Time & Space Analysis
💬 Want to see the same solution using sorting and two pointers? Comment below!
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