In this video, I solve LeetCode 7: Reverse Integer using a clean and effective string-based approach in JavaScript.
The challenge: Given a 32-bit signed integer x, return its digits reversed. If the reversed integer overflows 32-bit signed integer range, return 0.
My approach uses:
✅ Math.abs() to handle negatives
✅ JavaScript string methods: toString(), split(), reverse(), join()
✅ Careful edge case handling for 32-bit overflow
I made a mistake saying space complexity is O(1), it is O(n) instead because of the string and array operations — where n is the number of digits in the number.
Time Complexity: O(n)
Space Complexity: O(n) not O(1)
Chapters:
0:00 - Problem Overview
0:55 - Explanation
3:10 - Code Solution
4:25 - 32-bit Overflow Handling
5:40 - Time & Space Complexity
💬 Want to see this solved using pure math with O(1) space? Let me know in the comments!
#leetcode7 #reverseinteger #javascript #stringmanipulation #codinginterview #leetcodejavascript #algorithmpractice #interviewprep
En esta página del sitio puede ver el video en línea LeetCode 7: Reverse Integer in JavaScript | String Trick ✅ de Duración hora minuto segunda en buena calidad , que subió el usuario Crappy Coder 10 junio 2025, comparta el enlace con amigos y conocidos, en youtube este video ya ha sido visto 29 veces y le gustó 2 a los espectadores. Disfruta viendo!