How to fix mutable default argument in function leads to unexpected behavior... in Python
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We're excited to share with you our newest video, "How to solve mutable default argument in function leads to unexpected behavior. Use a=None and check if a is None inside the function then assign a=[]. in Python". 🎥 This series is meticulously designed to arm you with knowledge 🧠 and skills 🛠️ to overcome frequent coding challenges.
Today, we will decipher 🔎 and resolve a common error faced by Python coders: the bit hard to solve mutable default argument in function leads to unexpected behavior. Use a=None and check if a is None inside the function then assign a=[].. Here is a snapshot of the code of the video:
Troubling Scenario: ❗️
def append_to_list(value, a=[]):
a.append(value)
return a
list1 = append_to_list(1)
list2 = append_to_list(2)
print(list1)
print(list2)
Unwanted Result: 🚫
mutable default argument in function leads to unexpected behavior. Use a=None and check if a is None inside the function then assign a=[].
Effective Resolution: ✔️
def append_to_list(value, a=None):
if a is None:
a = []
a.append(value)
return a
list1 = append_to_list(1)
list2 = append_to_list(2)
print(list1)
print(list2)
Desired Output: 🏁
[1]
[2]
In this detailed walkthrough, we will illuminate 💡 the underlying cause of this error, and offer a comprehensive explanation: In Code1, `a=[]` creates a persistent list shared by all calls lacking a specific list argument. Code2 fixes this by initializing `a` inside the function if it hasn't been supplied. 🎯
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