Merge Sorted Array Java Solution | LeetCode Tutorial | 2 pointers | Sorting | Java Solution

Pubblicato il: 02 luglio 2023
sul canale di: Tech Fusion ai | Java Tutorials | Java DSA
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In this tutorial, we will solve the "Merge Sorted Array" problem from LeetCode using Java. The problem provides us with two integer arrays, nums1 and nums2, both sorted in non-decreasing order. Additionally, we are given two integers, m and n, which represent the number of elements in nums1 and nums2, respectively.

Our goal is to merge the elements of nums1 and nums2 into a single array, maintaining the non-decreasing order. However, instead of returning the final sorted array, we are required to modify nums1 in place to store the merged elements.

To accomplish this, we need to perform the following steps:

Create three pointers: p1, p2, and p, initially set to m-1, n-1, and m+n-1 respectively. These pointers will help us iterate through nums1 and nums2 in reverse order and also keep track of the position where we need to insert the merged elements.
While p1 and p2 are both greater than or equal to 0:
Compare the elements nums1[p1] and nums2[p2].
If nums1[p1] is greater than nums2[p2], set nums1[p] to nums1[p1] and decrement p1 and p by 1.
Otherwise, set nums1[p] to nums2[p2] and decrement p2 and p by 1.
After the above loop, there are two possibilities:
If there are any remaining elements in nums2, copy them to nums1 starting from index 0 up to p2+1.
If there are any remaining elements in nums1, they are already in their correct positions.
Finally, we will provide the solution to the problem by implementing the above steps in Java. By the end of this tutorial, you will have a clear understanding of how to merge two sorted arrays in a non-decreasing order efficiently.

Keywords:
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