Number Complement | Multiple Approaches | Leetcode 476 | codestorywithMIK
Whatsapp Community Link : https://whatsapp.com/channel/0029Va6k...
This is the 52nd Video of our Playlist "Leetcode Easy : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve an easy problem : Number Complement | Multiple Approaches | Leetcode 476 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Number Complement | Multiple Approaches | Leetcode 476 | codestorywithMIK
Company Tags : Cloudera
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie...
Leetcode Link : https://leetcode.com/problems/number-...
My DP Concepts Playlist : • Roadmap for DP | How to Start DP ? | Topic...
My Graph Concepts Playlist : • Graph Concepts & Qns - 1 : Graph will no m...
My Recursion Concepts Playlist : • Introduction | Recursion Concepts And Ques...
My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Intervie...
Instagram : / codestorywithmik
Facebook : / 100090524295846
Twitter : / cswithmik
Subscribe to my channel : / @codestorywithmik
╔═╦╗╔╦╗╔═╦═╦╦╦╦╗╔═╗
║╚╣║║║╚╣╚╣╔╣╔╣║╚╣═╣
╠╗║╚╝║║╠╗║╚╣║║║║║═╣
╚═╩══╩═╩═╩═╩╝╚╩═╩═╝
Summary :
Approach 1 (Using bit magic of XOR):
This approach calculates the total number of bits required to represent the given number num and then flips each bit one by one using the XOR operation with 1. This flips the bits, effectively giving the complement.
Time Complexity: O(log₂(num))
Space Complexity: O(1)
Approach 2 (Using XOR mask):
This method creates a mask with all bits set to 1 that matches the bit length of num. Then, it XORs num with this mask, flipping all bits to get the complement. The mask is generated by left-shifting and OR-ing bits until it covers all bits of num.
Time Complexity: O(log₂(num))
Space Complexity: O(1)
Approach 3 (Iterate digit by digit and create complement):
In this approach, you iterate through the bits of num and construct the complement bit by bit. If the current bit of num is 0, you set the corresponding bit in the result to 1. This continues until all bits are processed.
Time Complexity: O(log₂(num))
Space Complexity: O(1)
Each approach leverages different bit manipulation techniques to compute the complement efficiently.
✨ Timelines✨
00:00 - Introduction
#coding #helpajobseeker #easyrecipes #leetcode #leetcodequestionandanswers #leetcodesolution #leetcodedailychallenge #leetcodequestions #leetcodechallenge #hindi #india #coding #helpajobseeker #easyrecipes #leetcode #leetcodequestionandanswers #leetcodesolution #leetcodedailychallenge#leetcodequestions #leetcodechallenge #hindi #india #hindiexplanation #hindiexplained #easyexplaination #interview#interviewtips #interviewpreparation #interview_ds_algo #hinglish #github #design #data #google #video #instagram #facebook #leetcode #computerscience #leetcodesolutions #leetcodequestionandanswers #code #learning #dsalgo #dsa #newyear2024
In questa pagina del sito puoi guardare il video online Number Complement | Multiple Approaches | Leetcode 476 | codestorywithMIK della durata di ore minuti seconda in buona qualità , che l'utente ha caricato codestorywithMIK 21 agosto 2024, condividi il link con amici e conoscenti, su youtube questo video è già stato visto 7,040 volte e gli è piaciuto 341 spettatori. Buona visione!
