Master Java : Solve HackerRank Scanner Problems with Ease
Join us as we take on various coding challenges on HackerRank and show you how to tackle them with ease! Whether you're a beginner or an experienced programmer, this series will provide you with tips, tricks, and solutions to help you improve your coding skills and tackle tough problems with confidence. So sit back, grab a notebook, and let's dive into the world of coding challenges on HackerRank!
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Questions:
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Most HackerRank challenges require you to read input from stdin (standard input) and write output to stdout (standard output). One popular way to read input from stdin is by using the Scanner class and specifying the Input Stream as System.in. For example: Scanner scanner = new Scanner(System.in);
String myString = scanner.next();
int myInt = scanner.nextInt();
scanner.close(); System.out.println("myString is: " + myString);
System.out.println("myInt is: " + myInt);
The code above creates a Scanner object named and uses it to read a String and an int. It then closes the Scanner object because there is no more input to read, and prints to stdout using System.out.println(String). So, if our input is: Hi 5
Our code will print: myString is: Hi
myInt is: 5
Alternatively, you can use the BufferedReader class. Task
In this challenge, you must read integers from stdin and then print them to stdout. Each integer must be printed on a new line. To make the problem a little easier, a portion of the code is provided for you in the editor below. Input Format There are lines of input, and each line contains a single integer. Sample Input 42
100
125
Sample Output 42
100
125?
Answer:
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import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(Top Up Cs);
while (scan.hasNextInt()) {
int num = scan.nextInt();
System.out.println(num);
}
scan.close();
}
}
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