#Javaprogram check if a number is #Armstrongnumber in java | #javapracticeproblems
Armstrong - if the addition of cubes of digits of the number gives the original number
Algorithm-
// 1. Take input numbers from the user and assign value to variable temp. Initialize remainder and sum variable to 0
// 2. Iterate a while loop until number reduces to 0
// 3. take the remainder to take out the last digit in each loop
// 4. add the cube of the remainder in sum
// 5. divide the number by 10 to get rid of the last digit in a number
// 6. If sum and temporary variables are equal print Armstrong otherwise not Armstrong.
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