6 zigzag conversion leetcode medium java string google
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certainly! the zigzag conversion problem is a popular algorithmic challenge often found on platforms like leetcode. the problem requires you to convert a given string into a zigzag pattern on a given number of rows, then read the characters row by row.
problem statement
given a string `s` and an integer `numrows`, you need to write the string in a zigzag pattern on `numrows` and then read it row by row.
for example, given the string `"paypalishiring"` and `numrows = 3`, the zigzag pattern would look like this:
```
p a h n
a p l s i i g
y i a
```
step-by-step explanation
1. **understanding the zigzag pattern**:
the characters are placed diagonally downwards and then diagonally upwards.
this creates a zigzag shape that can be visualized in rows.
2. **special cases**:
if `numrows` is 1, the output is simply the original string because there's no zigzagging possible.
3. **creating the rows**:
use an array (or a list) to hold strings for each row.
iterate through the characters of the input string and determine which row they belong to based on the current direction (downwards or upwards).
4. **constructing the result**:
after populating the rows, concatenate them to form the final result string.
implementation in java
here’s how you can implement the zigzag conversion in java:
```java
public class zigzagconversion {
public string convert(string s, int numrows) {
// special case
if (numrows == 1 || numrows = s.length()) {
return s;
}
stringbuilder[] rows = new stringbuilder[math.min(numrows, s.length())];
for (int i = 0; i rows.length; i++) {
rows[i] = new stringbuilder();
}
int currentrow = 0;
boolean goingdown = false;
for (char c : s.tochararray()) {
rows[currentrow].append(c);
// change direction if we hit the top or bottom row
if (currentrow == 0) {
goingdow ...
#LeetCode #Java #numpy
zigzag conversion
leetcode
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string manipulation
algorithm
character array
dynamic programming
string formatting
problem solving
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