SQL Problem Solving: Last User Location on Each Day | RANK Window Function Tutorial

Pubblicato il: 16 agosto 2023
sul canale di: Rahul Upadhyay
640
24

Join us in this SQL problem-solving session as we unravel the challenge of tracking the last location where a user was spotted on each day. Leveraging the versatile RANK window function, we'll provide you with a step-by-step tutorial. Whether you're a SQL enthusiast or preparing for interviews, this tutorial is designed for you.

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Table creation & insertion script:
CREATE TABLE visit_log(
user_id int,
user_name varchar(20),
user_visit_location varchar(20),
user_visit_time datetime DEFAULT current_timestamp
);

INSERT INTO visit_log(user_id,user_name,user_visit_location,user_visit_time) VALUES(108,'Shivangi Kumari','Bengaluru','2022-08-01 01:15:00.980'),
(123,'Yuvraj Sinha','Jaipur','2022-08-25 03:55:00.050'),
(108,'Shivangi Kumari','Pune','2022-08-06 09:23:00.510'),
(108,'Shivangi Kumari','Mumbai','2022-08-06 22:00:05.100'),
(159,'Priti Dubey','Lucknow','2022-08-28 10:20:00.260'),
(123,'Yuvraj Sinha','Bengaluru','2022-08-25 20:13:00.110'),
(159,'Priti Dubey','Chennai','2022-08-20 06:00:00.560'),
(120,'Jai Dixit','Delhi','2022-08-11 08:25:00.430');

#sql #interview #datefunction #rank #sqlqueries


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