Reverse engineering challenge. Java Byte code. In this video i explained what is java byte code and talked about some instructions before start solving our real problem. First part a short intro to java byte code and how to read them. This time we use only static analysis no ida pro and other reverse engineering tools. I shared what i have learned while solving this problem. Explained in Bengali.
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Note: Before you see the solution try it yourself then again came here for the solution. By doing this you will learn more by yourself.
In solution i used [flag = -2147483648 ] because in 32bit the maximum value is 2^31 -1 and 2^31 -1 = 2147483648 . As we are comparing our xor result with negative one we are taking -ve 2147483648 .
Link for the problem : https://ctflearn.com/challenge/368
Link for the solution : https://github.com/Purnendu-tudu/yout...
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