First Repeating Element || Array || Finding the first repeating element step-by-step || build logic
The provided solution aims to find the position of the first repeating element in an array. The initial code uses a nested loop to check each pair of elements, resulting in a time complexity of O(n^2). The optimized version leverages a hash map to track the frequency of each element in a single pass through the array. In the first loop, it populates the hash map with the counts of each element. In the second loop, it checks the hash map for the first element with a count greater than one and returns its 1-based index. If no repeating element is found, it returns -1. This optimized approach improves the time complexity to O(n) while maintaining a space complexity of O(n).
problem link - https://www.geeksforgeeks.org/problem...
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