Sherlock and the Valid String Java Coding Challenge | HackerRank | Edabit | How'd You Code That?

Publicado em: 14 Junho 2020
no canal de: Ed Clark

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Sherlock and the Valid String on HackerRank: https://www.hackerrank.com/challenges...

Sherlock and the Valid String on Edabit: https://edabit.com/challenge/Mgrj26S3...

Sherlock considers a string to be valid if all characters of the string appear the same number of times. It is also valid if he can remove just 1 character at 1 index in the string, and the remaining characters will occur the same number of times. Given a string s, determine if it is valid.
If so, return YES, otherwise return NO.

For example, If s is equal to “abc”, the string is valid because the frequencies of characters are all the same. If s is equal to “abcc”, the string is also valid, because we can remove 1 “c” and have one of each character remaining in the string. However, if s is equal to “abccc”, the string is not valid, because removing one character does not result in the same frequency of characters.

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