Minimum Cost Path Dynamic Programming Explained with Code | Leetcode #64
Please consume this content on nados.pepcoding.com for a richer experience. It is necessary to solve the questions while watching videos, nados.pepcoding.com enables that.
NADOS also enables doubt support, career opportunities and contests besides free of charge content for learning. In this video, we discuss the solution for the Minimum Cost Path problem where we are required to reach the bottom right corner from the top left corner with minimum cost. For a better understanding of the problem, click here: • Minimum Cost Path - Question | Dynami... . In this problem,
1. You are given a number n, representing the number of rows.
2. You are given a number m, representing the number of columns.
3. You are given n*m numbers, representing elements of 2d array a, which represents a maze.
4. You are standing in top-left cell and are required to move to bottom-right cell.
5. You are allowed to move 1 cell right (h move) or 1 cell down (v move) in 1 motion.
6. Each cell has a value that will have to be paid to enter that cell (even for the top-left and bottom-right cell).
7. You are required to traverse through the matrix and print the cost of path which is least costly.
For a better experience and more exercises, VISIT: https://www.pepcoding.com/resources/o...
#dp #dynamicprogramming #mincostpath
Have a look at our result: https://www.pepcoding.com/placements
Follow us on our FB page: / pepcoding
Follow us on Instagram: / pepcoding
Follow us on LinkedIn: / pepcoding-education
Nesta página do site você pode assistir ao vídeo on-line Minimum Cost Path Dynamic Programming Explained with Code | Leetcode #64 duração hora minuto segundo em boa qualidade , que foi baixado pelo usuário Pepcoding 31 Julho 2020, compartilhe o link com seus amigos e conhecidos, no youtube este vídeo já foi visto 60,435 vezes e gostou 1.3 mil espectadores. Boa visualização!
