Big Integer Exponentiation & Modular Power in Python – Long Version + One-Liner

Опубликовано: 23 Апрель 2025
на канале: CodeVisium
158
1

Python’s integers are arbitrary-precision, meaning you can compute extremely large powers without overflow, unlike fixed-width types in C++[^0^]​
Python documentation

Below are two implementations:

Compact One-Liner: Performs the same computation in a single expressive line, ideal for code-golf or succinct contest submissions.

Both approaches correctly handle very large inputs, leveraging Python’s optimized big-integer arithmetic and the optional third argument of pow() for modular reduction[^5^]​

Long-Form Script

Read four integers a, b, c, d from input (each on its own line)
a = int(input().strip())
b = int(input().strip())
c = int(input().strip())
d = int(input().strip())

Compute a**b and c**d using Python's built-in exponentiation
result1 = pow(a, b) # equivalent to a ** b
result2 = pow(c, d) # equivalent to c ** d

Print the sum of the two large powers
print(result1 + result2)
Explanation of Steps:

int(input().strip()) parses each line as a Python integer, supporting any size[^0^]​

pow(a, b) uses Python’s built-in for exact integer exponentiation in O(log b) time[^3^]​

Summing two big integers is also handled natively with arbitrary precision[^0^]​

Compact One-Liner
Read input lines and compute (a**b + c**d) in one statement
print(pow(int(input()), int(input())) + pow(int(input()), int(input())))

One-Liner Breakdown:

Each int(input()) reads and converts a line to an integer.

pow(...) computes each power efficiently[^2^]​

The + operator adds the two results, and print() outputs the final big integer.


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