Program40 | Tutorial #40 | Find the Second Largest Element in an Array in Java
In this video (Program40 | Tutorial #40), we solve an important array interview question — finding the second largest element in an array using Java.
This tutorial is part of my Core Java Logic Building Series, where we practice beginner to interview-level Java programs step by step.
🔹 What you will learn in this tutorial:
Taking array input using Scanner
Sorting an array in descending order
Using nested loops for comparison
Swapping elements in Java
Finding the second largest value in an array
🔹 Example:
Input: [10,5,20,8]
Sorted: [20,10,8,5]
Output: 10
🔹 Approach Used:
Sort the array in descending order (Largest → Smallest)
The element at index 1 becomes the second largest element
🔹 Program Flow:
User enters array size
User inputs array elements
Program sorts the array in descending order
The second element is selected
Second largest number is printed
🔹 Concepts Covered:
Array traversal
Nested loops
Swapping technique
Descending order sorting
Second maximum logic
🔹 Why this program is important?
Very common Java interview question
Builds foundation for advanced array problems
Helps before learning optimized max/second-max algorithms
🔹 Who should watch this?
Java beginners
Core Java learners
BCA / MCA / BTech students
Java interview preparation
Coding practice beginners
📌 Second largest element questions are frequently asked in coding interviews.
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