"Find HCF/GCD using for loop", C++ PROGRAM.
The logic of this program is simple.
In this program, the smaller integer between [ n1 ] & [ n2 ] is stored in [ n2 ]. Then the loop is iterated from i=1 to i is less than equal to n2 and in each iteration, the value of i is increased by 1.
If both numbers are divisible by [ i ] then, that number is stored in variable [ hcf ].
This process is repeated in each iteration. When the iteration is finished, HCF will be stored in variable [ hcf ].
Source Code link :
https://codesayswebsite.blogspot.com/...
CodeSays Website link :
https://codesayswebsite.blogspot.com/
All Source Codes are available here :
https://codesayswebsite.blogspot.com/
#COMPUTERLANGUAGE :)
En esta página del sitio puede ver el video en línea Find HCF/GCD using for loop || C++ PROGRAM de Duración hora minuto segunda en buena calidad , que subió el usuario CodeSays 09 junio 2021, comparta el enlace con amigos y conocidos, en youtube este video ya ha sido visto 720 veces y le gustó 12 a los espectadores. Disfruta viendo!