Find HCF/GCD using for loop || C++ PROGRAM

Publicado em: 09 Junho 2021
no canal de: CodeSays
720
12

"Find HCF/GCD using for loop", C++ PROGRAM.

The logic of this program is simple.

In this program, the smaller integer between [ n1 ] & [ n2 ] is stored in [ n2 ]. Then the loop is iterated from i=1 to i is less than equal to n2 and in each iteration, the value of i is increased by 1.

If both numbers are divisible by [ i ] then, that number is stored in variable [ hcf ].

This process is repeated in each iteration. When the iteration is finished, HCF will be stored in variable [ hcf ].


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